A pair of dice is thrown once. Find the probability of getting an even number on the first side.
Probability defines the likelihood of occurrence of an event
Answer: The probability of getting an even number on the first side when a pair of dice is thrown once is 1/2
Let's look into the possible outcomes.
Explanation:
Sample space of a pair of dice thrown has the following possible outcomes:
{(1,1) , (1,2) , (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6),(4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
Total number of outcomes = 36
Let E be the event of getting an even number on the first side.
Thus, favourable outcomes of event E is as follows:
{(2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}
Total number of favourable outcomes = 18
Using the probability formula,
Probability = Number of favorable outcomes / Total number of outcomes
Thus, the probability of getting an even number on the first side = 18/36 = 1/2.
Therefore, the probability of getting an even number on the first side when a pair of dice is thrown once is 1/2.
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