Consider circle T with radius 24 in and θ = 5pi/6 radians. What is the length of minor arc SV?
20π in, 28π in, 40π in, 63π in.

Solution:

Given: Radius(r) = 24in and central angle(θ) = 5pi/6 radians

For a circle, the distance along the arc is the arc length of the circle.

S = r × θ --- (1)

Where r is the radius and θ is the central angle

Substituting these values in (1)

S = 24 × 5π/6

So we get,

S = 20π

Therefore, the length of minor arc SV is 20π in.

Consider circle T with radius 24 in and θ = 5pi/6 radians. What is the length of minor arc SV?

Summary:

Consider circle T with radius 24 in and θ = 5pi/6 radians then the length of minor arc SV is 20π in.