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# Factor completely 16x^{2} - 25.

(4x - 5)(4x - 5), (4x + 5)(4x - 5), (16x + 5)(x - 5), (16x - 5)(x + 5)

**Solution:**

To factorise completely, we will use the algebraic identity a^{2} - b^{2}

The equation 16x^{2} - 25 can be written as (4x)^{2} - (5)^{2}.

Using the algebraic identity, we factor the polynomial as

a^{2} - b^{2} = (a + b)(a - b) where a = 4x and b = 5

(4x)^{2} - (5)^{2} = (4x + 5)(4x - 5)

## Factor completely 16x^{2} - 25.

**Summary:**

The factors of 16x^{2} - 25 are (4x + 5)(4x - 5) using the algebraic identity a^{2} - b^{2} = (a + b)(a - b)

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