Find an equation of the line having the given slope 4 and containing the given point (6, 11).
In this problem, we use the concept of the point-slope form of the straight line to find the equation.
Answer: The equation in slope-intercept form of the line through the point (6, 11) with slope 4 is given as y = 4x - 13.
Let us see how we solve the problem in detail.
Let us consider a point on the line (x, y).
We know that given two points (x1, y1) and (x2, y2) the slope is given by,
Slope(m) = (y2 - y1) / (x2 - x1)
Here, m = 4
Hence, slope of the line passing through the points (6, 11) and (x, y) is,
(y - 11) / (x - 6) = 4
y - 11 = 4(x - 6)
y = 4x - 24 + 11
y = 4x - 13