# Find the value of the expression 2x^{3} + 3y^{2} - 17 when x = 3 and y = 4.

**Solution:**

2x^{3} + 3y^{2} - 17 [Given]

Substitute x = 3 and y = 4 in the given algebraic expression

= 2 (3)^{3} + 3(4)^{2} - 17

By further calculation

= 2 (27) + 3 (16) - 17

So we get

= 54 + 48 - 17

= 102 - 17

= 85

Therefore, the value of the expression is 85.

## Find the value of the expression 2x^{3} + 3y^{2} - 17 when x = 3 and y = 4.

**Summary: **

The value of the expression 2x^{3} + 3y^{2} - 17 when x = 3 and y = 4 is 85.