# How do you find the vertex of a quadratic function? Find the vertex of quadratic function y = x^{2} + 2x - 2 .

We will use the concept of differentiation in order to find the vertex of a quadratic function.

## Answer: The vertex of quadratic function y = x^{2} + 2x - 2 is given by point (-1, -3)

Let us see how we will use the concept of differentiation in order to find the vertex of a quadratic function.

**Explanation:**

The point where a quadratic equation has a vertex is the point where dy / dx = 0.

Hence, let us calculate dy / dx for the quadratic function y = x^{2} + 2x - 2.

On differentiating both sides we get,

dy / dx = 2x + 2.

Now substituting dy / dx = 0, we get

0 = 2x + 2

⇒ x = -1

Substitute x = -1 in y = x^{2} + 2x - 2

y = x^{2} + 2x - 2

y = (-1)^{2} + 2(-1) - 2 = -3

Thus, the points are x = -1 and y = -3.