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# How do you use the discriminant to find the number of real solutions of the following quadratic equation: 2x^{2}+4x+2=0.

**Solution:**

Roots of the quadratic equation of the form ax^{2}+bx+c=0 are given by the expression:

[-b ± √b² - 4ac]/2a

Hence the roots of the given equation are:

b = 4; a = 2; c = 2

The root(s) are = - 4 ± √(4)² - 4(2)(2) = - 4 ± √16 - 16 = -4 ± √0 = -1

Since the discriminant b² - 4ac is equal to zero, it implies the quadratic equation has two equal real and rational roots.

## How do you use the discriminant to find the number of real solutions of the following quadratic equation: 2x^{2}+4x+2=0.

**Summary:**

The discriminant (b² - 4ac) value is zero hence roots are real and equal

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