In parallelogram EFGH, EJ = x² - 4 and JG = 3x .What is EG?

Solution:

Given EJ = x² - 4 and JG = 3x

The diagonals of the parallelogram bisect each other. Thus EJ = JG

x² - 4= 3x

 x² - 4 - 3x= 0

(x - 4)(x + 1)=0

x = -1, 4

we know that EG =  EJ + JG

EG = x² - 4 +3x

Taking the positive value, let us consider x = 4

When x = 4, EG = 16 - 4 +12=24

Therefore, EG =24

In parallelogram EFGH, EJ = x² - 4 and JG = 3x .What is EG?

Summary:

In parallelogram EFGH, EJ = x² - 4 and JG = 3x , EG is 24