Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth.
Solution:
Given,
3x2 + x + 10 = 0.
For using complete square method, the equation must be in the from
x2 + bx =c.
3x2 + x + 10 = 0.
Subtract 10 from both sides of the equation.
3x2 + x = -10.
Divide both sides by 3.
3x2 + x/3 = -10/3
Dividing by 3 undoes the multiplication of 3.
x2 + 1/3x = -10/3.
Making the equation a perfect square,
x2 +1/3x + (1/6)2 = -10/3 + (1/6)2
Squaring we get,
x2 + 1/3x + 1/36 = -10/3 + 1/36
x2 +1/3x + 1/36 = -119/36
Factoring, we get,
(x + 1/6)2 = -119/36
Taking square root on both sides,
√(x + 1/6)2 =√-119/36
Simplifying we get,
x + 1/6 = √119i/6
x + 1/6 = - √119i/6
Subtracting 1/6 from both sides,
x = (-1 + √119i)/6
x = (- √119i - 1)/6
x = (-1 +√119i)/6 ≈ 1.818i
x = (- √119i - 1)/6 ≈ 1.818i
Therefore, the solution is 1.818i.
Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth.
Summary:
Solving 3x2 + x + 10 = 0 the solutions to the nearest hundredth is 1.818i
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