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# Solve the system of equations. x + 3y = -1 and 2x + 2y = 6

**Solution:**

Given, the system of equations are

x + 3y = -1

x = -3y - 1 --- (1)

2x + 2y = 6 --- (2)

Substitute (1) in (2),

2(-3y - 1) + 2y = 6

-6y - 2 + 2y = 6

Grouping of common terms,

-6y + 2y = 6 + 2

-4y = 8

y = 8/-4

y = -2

Put y = -2 in (1)

x = -3(-2) - 1

x = 6 - 1

x = 5

Therefore, the solutions are x = 5 and y = -2.

## Solve the system of equations. x + 3y = -1 and 2x + 2y = 6

**Summary:**

The solutions to the system of equations. x + 3y = -1 and 2x + 2y = 6 are x = 5 and y = -2.

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