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# The Sum of Four Consecutive Odd Integers is 216. What are the Four Integers?

Let us find the four integers when the sum of those consecutive odd integers is given.

## Answer: The four consecutive integers whose sum is 216 are 51, 53, 55 and 57.

Let us understand it with the help of a detailed explanation.

**Explanation:**

Let the first integer of the four integers be n.

Since the 4 numbers are consecutive and odd, they differ by 2.

So, the numbers will be n, (n+2), (n+4), and (n+6).

(n) + (n+2) + (n+4) + (n+6) = 216 (given)

Therefore, 4n + 12 = 216

4n = 216-12 = 204

n= 204/4

n= 51

So, n +2 = 53

n+4 = 55

n+6 = 57

### Thus, the four consecutive odd integers whose sum is 216 are 51, 53, 55, and 57.

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