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The Sum of Four Consecutive Odd Integers is 216. What are the Four Integers?
Answer: The four consecutive integers whose sum is 216 are 51, 53, 55 and 57.
Let us understand it with the help of a detailed explanation.
Let the first integer of the four integers be n.
Since the 4 numbers are consecutive and odd, they differ by 2.
So, the numbers will be n, (n+2), (n+4), and (n+6).
(n) + (n+2) + (n+4) + (n+6) = 216 (given)
Therefore, 4n + 12 = 216
4n = 216-12 = 204
So, n +2 = 53
n+4 = 55
n+6 = 57
Thus, the four consecutive odd integers whose sum is 216 are 51, 53, 55, and 57.