What are the vertex and the axis of symmetry of the equation y = -2x² + 8x - 10.

Solution:

Given equation

y = -2x² + 8x - 10.

For y = a(x - h)² + k ,

The axis of symmetry is x - h = 0, vertex is (h, k).

Now we can write y = 2x² - 8x - 10 as follows

y = 2(x² - 4x + 4) - 8 - 10

or y = 2(x - 2)² -18

By comparing with the standard equations we get

Axis of symmetry is x - 2 = 0 and the vertex is (2,-18).

Therefore, the vertex and the axis of symmetry of the equation y = -2x² + 8x - 18 is (2,-18) and the axis of symmetry is x - 2 = 0.

What are the vertex and the axis of symmetry of the equation y = -2x² + 8x - 10.

Summary:

The vertex and the axis of symmetry of the equation y = -2x² + 8x - 10 are x - 2 = 0 and (2, -18) respectively.