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# What is the 10th term of the sequence 64, 16, 4

**Solution:**

The __sequence__ 64, 16, 4 ….is a geometric series with

__Common ratio__ = r = 16/64 = 4/16 = 1/4

The first term is a = 64

The nth term of a __geometric series__ is given as

T_{n} = ar^{n - 1}

T_{10} = 64(1/4)^{10 - 1}

= 64(1/4)^{9}

= 4^{3} × 4^{-9}

= 4^{-6}

= 1/4^{6}

= 1/4096

## What is the 10th term of the sequence 64, 16, 4

**Summary:**

The 10th term of the sequence 64, 16, 4 is 1/4^{6} or 1/4096

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