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# Which is the equation of the line that contains points (8, 10) and (-4, 2)?

y - 8 = 3/2 (x - 10 )

y - 10 = 3/2 (x - 8)

y - 10 = 2/3 (x - 8)

y - 8 = 2/3 (x - 10)

**Solution:**

The given points are (8, 10) and (-4, 2)

The equation of a line which passess through the points (x_{1}, y_{1}) and (x_{2}, y_{2}) is

y - y_{1} = m (x - x_{1})

Where m is the slope

m = (y_{2} - y_{1})/ (x_{2} - x_{1})

By substituting the values

m = (2 - 10)/ (-4 - 8)

m = -8/-12

m = 2/3

Now substituting the value of m

y - 10 = 2/3 (x - 8)

Using the multiplicative distributive property

y - 10 = 2x/3 - 16/3

y = 2x/3 - 16/3 + 10

By further calculation

y = 2x/3 - (16 - 30)/3

y = 2x/3 + 14/3

Therefore, the equation of the line is y - 10 = 2/3 (x - 8).

## Which is the equation of the line that contains points (8, 10) and (-4, 2)?

**Summary:**

The equation of the line that contains points (8, 10) and (-4, 2) is y - 10 = 2/3 (x - 8).

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