# What is the remainder when the polynomial 6x^{2 }+ 11x - 7 is divided by 2x - 1?

**Solution :**

We will apply the concepts of factorization and polynomial to find the remainder.

We have a 2-degree polynomial divided by a linear polynomial.

Now , 2x - 1 = 0 . So by substituting x = 1 / 2 in the equation we will get the remainder. [remainder theorem of the polynomial]

Let us substitute now x = 1 / 2 in the quadratic equation i.e. 6x^{2 }+ 11x - 7 .

= 6 × (1 / 2)^{2} + 11 × (1 / 2) - 7

= 6 / 4 + 11 / 2 - 7

= 0

We can also perform long division

Hence, the remainder when 6x^{2 }+ 11x − 7 is divided by 2x - 1 is 0 .

## What is the remainder when the polynomial 6x^{2 }+ 11x - 7 is divided by 2x - 1?

**Summary:**

When 6x^{2 }+ 11x - 7 is divided by 2x - 1 then the remainder is 0.

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