BODMAS is used to explain the order of operation in a mathematical expression.
According to the BODMAS rule, the B - brackets are at the highest priority and hence, we will be evaluating all the brackets separately
Solving first bracket:
[3 × {(-5) × (-4)}]
= [3 × 20] = 60 ------------- (1)
Solving second bracket:
{27 + (-13-4)}
=27 + (-17) = 10 -------------- (2)
Solving third bracket :
[{27 × (-2)} ÷ (-3 - 3)]
= [-54 ÷ (-3 - 3)] (since, {27 × (-2)} = -54 )
= [-54 ÷ (-6)] = 9 --------------- (3)
Solving the last breacket
[{(-3) × (-3) × 5} ÷ (-3)]= {45 ÷ (-3)} = -15 (since, (-3) × (-3) × 5} = 45) -------------------- (4)
Substituting the obtained values (1), (2), (3) and (4) in the given expression we get,
[3 × {(-5) × (-4)}] ÷ {27 + (-13 - 4)} + [{27 × (-2)} ÷ (-3 - 3)] + [{(-3) × (-3) × 5} ÷ (-3)]= 60 ÷ 10 + 9 + (-15)
= 6 + 9 - 15
= 6 - 6
= 0
Hence, the value of [3 × {(-5) × (-4)}] ÷ {27 + (-13 - 4)} + [{27 × (-2)} ÷ (-3 - 3)] + [{(-3) × (-3) × 5} ÷ (-3)] is 0
What is the Value of given expression? [3 × {(-5) × (-4)}] ÷ {27 + (-13 - 4)} + [{27 × (-2)} ÷ (-3 - 3)] + [{(-3) × (-3) × 5} ÷ (-3)]
Summary:
The value of the given expression [3 × {(-5) × (-4)}] ÷ {27 + (-13 - 4)} + [{27 × (-2)} ÷ (-3 - 3)] + [{(-3) × (-3) × 5} ÷ (-3)] is 0