Which of the following shows 9x2y - 4x + 3y3x - 2y2 written in standard form.
9x2y - 4x + 3y3x - 2y2
3y3x - 2y2 + 9x2y - 4x
9x2y - 4x - 2y2 + 3y3x
3y3x + 9x2y - 2y2 - 4x
Solution:
Given, the expression is 9x2y - 4x + 3y3x - 2y2
We have to write this expression in a standard form.
We can arrange each term as the reducing degree of each term.
Degree of 9x2y = degree of x + degree of y
= 2 + 1
= 3
Degree of 4x = 1
Degree of 3y3x = degree of x + degree of y
= 1 + 3
= 4
Degree of 2y2 = 2
Now arrange the expression in descending order of degree,
3y3x + 9x2y - 2y2 - 4x
Therefore, the expression in standard form is 3y3x + 9x2y - 2y2 - 4x.
Which of the following shows 9x2y - 4x + 3y3x - 2y2 written in standard form.
Summary:
The expression 9x2y - 4x + 3y3x - 2y2 written in standard form is 3y3x + 9x2y - 2y2 - 4x.
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