You toss a coin and roll a number cube. Find p(tail and a six).

Solution:

The ratio of the number of favorable outcomes to the total number of outcomes is called probability. The probability of an event always lies between 0 to 1.

P(E) = Number of possible outcomes / Total number of outcomes

Number of possible outcomes of getting a tail by tossing a coin = 1

Total number of outcomes by tossing a coin = 2

⇒ P (getting a tail) = 1/2 --------------- (1)

Number of possible outcomes of getting a 6 by rolling a number cube = 1

Total number of outcomes by rolling a number cube = 6

⇒ P (getting a six) = 1/6 ---------------- (2)

Given that both the events occured simultaneously.

Therefore,

⇒ P (tail and a six) = P (getting a tail) × P (getting a six)

⇒ P (tail and a six) = 1/2 × 1/6 [From (1) and (2)]

⇒ P (tail and a six) = 1/12

Thus, the probability of getting a tail and a six when a coin is tossed and a cube is rolled is 1/12.

You toss a coin and roll a number cube. Find p(tail and a six).

Summary:

The probability of getting a tail and a six when a coin is tossed and a cube is rolled is 1/12.