Counterexample is used to check the validity of an argument.
Consider the following statement: If a food is a fruit, then it is an apple.
Now, consider this statement: Mango is a food. It is a fruit, but it is not an apple.
Threfore, the mango is the counterexample, thereby making the first statement invalid.
Counterexamples are used in math to contradict a statement.
What is a Counterexample?
A counterexample is an example that meets the mathematical statement's condition, but does not lead to the statement's conclusion.
Instead of showing that the statement is true, we show that the statement is false using the counterexample.
Consider this situation where a teacher asks Benny about prime numbers
Teacher: Hey Benny, do you know about prime numbers?
Benny: Prime numbers are those numbers that are divisible by 1 and itself only.
Teacher: You are right! They cannot be factored further. What else can you say about the prime numbers?
Benny: All the prime numbers are odd.
Ron: But, the prime number 2 is even.
Teacher: 2 is a prime number. It meets the statement and does not meet the conclusion that it is odd. Thus 2 is the counterexample.
Thus the counterexample helps us in disproving the mathematical conjectures.
How can we identify Counterexamples?
Counterexamples are used to prove that a statement is invalid.
Identify the hypothesis and the conclusion in the given statement.
The counterexample must be true for hypothesis but false for the conclusion.
For example, let's identify the number 14 is a counterexample for which of the following conditional statements.
|a) If a number is even, then it ends with 2, 4, 6, 8, or 0.||Number is even||Number ends with 2, 4, 6, 8, or 0||14 is even and ends with 4.|
|b) If a number is divisible by 2, it is also divisible by 4.||Number is divisbile by 2||Number is also divisible by 4||14 is divisbile by 2,
but not divisible by 4.
|c) If a number is divisible by 2, then it is even.||Number is divisible by 2||Number is even.||14 is divisbile by 2,
and is even.
|d) If a number is odd, then its not divisble by 2.||Number is odd||Number is not divisble by 2||14 is not odd
and is divisible by 2.
A counterexample is true for hypothesis but false for the conclusion. Thus option 2 is the correct answer.
\(\therefore\) 14 is the counterexample for the 2nd statement that states "If a number is divisbile by 2, it is also divisible by 4."
Move any of the points on the left triangle every time you start with.
Move any points on the right triangle: angle A' will always be congruent to angle A, and angle B' will always be congruent to B.
Try connect the dots on the right triangle in a way that makes a triangle that is NOT similar to ABC?
If you create a triangle that is similar to ABC, you can see the ratios of the sides, in this counterexample calculator.
Can you make them be not quite equal?
Counterexamples are used to prove the limitations of possible theorems.
How do You Make a Counterexample?
'If' part must be true and 'then' part must be false.
If a number is a perfect square, then it is odd.
Let us try to set up a counterexample for this.
- 'If' part is a number that is a perfect square.
Think of 4 which is a perfect square.
This has become true.
- 'Then' part is that the number should be odd. 4 is even.
This has become false.
Thus we have set up a counterexample for the statement.
Counterexamples are used in geometry to prove the conditional statements false.
1) Conjecture: "All quadrilaterals of equal length are squares".
The counterexample is rhombus.
A rhombus has all sides of equal length, however the angles are not straight and thus it is not a square.
2) Conjecture: "The height of a triangle lies inside the triangle".
An altitude of a triangle is the perpendicular from a vertex to the opposite side.
It can also be at the outside of the triangle if the angle \(\geq 90 ^\circ\).
What is a Counterexample to The Conditional Statement?
A counterexample is an example in which the condition is true, but the conclusion is false.
If you can find a counterexample to a conditional statement, then that conditional statement is false.
Counterexample in Algebra
|Statement:||If \(a^2 > b^2\),
then a > b
Hypothesis is formed.
|Example:||\(5^2 > 2^2\)
25 > 4 and 5 > 2
|The condition is true and the conclusion is true.|
|Counter example:||\((-5)^2 > 2^2\)
25 > 4 but -5 \(\ngtr\) 2
|The condition is true but the conclusion is false.|
|Conclusion||\(\therefore\) If \(a^2 > b^2\),
then \(a>b\) is not true.
|Counter example makes the statement invalid|
Jim says “If n is an integer and \(n^2\) is divisible by 4, then n is divisible by 4.”
Prove that he is wrong.
To give a counterexample, we need to find the square of an integer such that it is divisible by 4
Let's try with 6!
\(6^2\) is divisible by 4 but 6 is not divisible by 4
Thus n = 6 is a counterexample to Jim's statement.
|\(\therefore\) n = 6 is the counterexample|
Raymond tells "If a perimeter of a rectangle is 14, then its area is 10."
Which of the following could be the counterexamples? Justify your decision.
a) a rectangle with sides measuring 2 and 5
b) a rectangle with sides measuring 10 and 1
c) a rectangle with sides measuring 1 and 5
d) a rectangle with sides measuring 4 and 3
Find which disproves the statement
a) Rectangle with sides 2 and 5: Perimeter = 14 and area = 10
Both 'if' and 'then' are true. So it is not a counterexample.
b) Rectangle with sides 10 and 1: Perimeter = 22 and area = 10
Both 'if' is false and 'then' is true. So it is not a counterexample.
c) Rectangle with sides 1 and 5: Perimeter = 12 and area = 5
Both 'if' and 'then' are false. So it is not a counterexample.
c) Rectangle with sides 4 and 3: Perimeter = 14 and area = 12
Both 'if' is true and 'then' is false. So it is a counterexample.
|\(\therefore\) Rectangle with sides 4 and 3 is the counterexample for the given statement.|
Colin examined the set of numbers in the box are multiples of 3. She claimed that they are divisible by 9. Do you agree or disagree? Justify your answer.
If a number is a multiple of 3, then it is divisible by 9 is the statement given by Colin.
To disprove let us find which is the counterexample among these.
a) 16 is not a multiple of 3. Thus the condition is false.
16 is not divisible by 9. Thus the conclusion is false.
So 16 is not a counterexample.
b) 27 is a multiple of 3.Thus the condition is true.
It is divisible by 9.Thus the conclusion is true.
So 27 is not a counterexample.
c) 24 is a multiple of 3. Thus the condition is true.
16 is not divisible by 9. Thus the conclusion is false.
So 24 is a counterexample.
|\(\therefore\) 24 is the counterexample for the given statement.|
Here are a few activities for you to practice. Select/Type your answer and click the "Check Answer" button to see the result.
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Frequently Asked Questions (FAQs)
1. What is the purpose of Counterexample?
Disproving by counterexample is the technique in maths where a statement is shown to be invalid by finding a single example whereby it is not satisfied.
2. Does a Counterexample always disprove a conjecture?
Yes. When examples prove the proof or therom or a conjecture, counterexamples disprove a conjecture.
3. How Counterexample helps in solving problems?
Using the counterexamples, we can produce meaningful statements and theorems.