# The 17^{th} term of an AP exceeds its 10^{th} term by 7. Find the common difference

An arithmetic sequence has a common difference between any two consecutive terms.

**Solution:**

The formula for n^{th} term of an AP is a_{n} = a + (n - 1) d

Here, a_{n} is the n^{th} term, a is the first term, d is the common difference and n is the number of terms.

a_{17} = a + (17 - 1)d

a_{17} = a + 16d

a_{10} = a + (10 - 1)d

a_{10} = a + 9d

According to the question, a_{17 }- a_{10} = 7 (given)

16d - 9d = 7

7d = 7

d = 1

Answer: The common difference is 1.

**Video Solution:**

## 17^{th} term of an AP exceeds its 10^{th} term by 7. Find the common difference

### NCERT Solutions Class 10 Maths Chapter 5 Exercise 5.2 Question 10 - Chapter 5 Exercise 5.2 Question 10:

17^{th} term of an AP exceeds its 10^{th} term by 7. Find the common difference

The common difference of the AP in which the 17th term exceeds the 10th term by 7 is 1