# A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was Rs.90, find the number of articles produced and the cost of each article

**Solution:**

Let the number of articles produced on one day be x.

Therefore, the cost (in rupees) of each article will be (3 + 2x)

The total cost of production = Cost of each article × Total number of articles

Let us use this relation to form a quadratic equation.

90 = (3 + 2x) (x)

90 = (3 + 2x) (x)

(3 + 2x) ( x) = 90

3x + 2x^{2} = 90

2x^{2} + 3x - 90 = 0

2x^{2} + 15x - 12x - 90 = 0

x(2x + 15) - 6(2x + 15) = 0

(2x + 15) (x - 6) = 0

2x + 15 = 0 and x - 6 = 0

2x = -15 and x = 6

x = -15/2 and x = 6

Number of articles cannot be a negative number.

Therefore, x = 6

Cost of each article = 3 + 2x

= 3 + 2 (6)

= Rs.15

Cost of each article is Rs.15.

Number of articles produced is 6.

**Video Solution:**

## A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the total cost of production on that day was ` 90, find the number of articles produced and the cost of each article

### Class 10 Maths NCERT Solutions - Chapter 4 Exercise 4.2 Question 6:

A cottage industry produces a certain number of pottery articles in a day. It was observed on a particular day that the cost of production of each article (in rupees) was 3 more than twice the number of articles produced on that day. If the cost of the production on that day is ₹ 90. Then the number of cotton produced and the cost of production is 6 and Rs.15 respectively.