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A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (i) 3 (ii) 12
Solution:
Since the fair coin has 1 marked on one face and 6 on the other, and the die has six faces that are numbered 1, 2,3, 4, 5 and 6, the sample space is given by
S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
Accordingly, n (S) = 12
(i) Let A be the event in which the sum of numbers that turn up is 3.
Accordingly, A = {(1, 2)}
Then the required probability is,
P (A) = Number of outcomes favourable to A/Total number of possible outcomes
= n (A)/n (S)
= 1/12
(ii) Let B be the event in which the sum of numbers that turn up is 12
Accordingly, B = {(6, 6)}
P (B) = Number of outcomes favourable to B/Total number of possible outcomes
= n (B)/n (S)
= 1/12
NCERT Solutions Class 11 Maths Chapter 16 Exercise 16.3 Question 5
A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Find the probability that the sum of numbers that turn up is (i) 3 (ii) 12.
Summary:
A fair coin with 1 marked on one face and 6 on the other and a fair die are both tossed. Then the probabilities of the given events are (i) 1/12 (ii) 1/12
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