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# A total of 25 patients admitted to a hospital are tested for levels of blood sugar, (mg/dl) and the results obtained were as follows :

87 71 83 67 85

77 69 76 65 85

85 54 70 68 80

73 78 68 85 73

81 78 81 77 75

Find mean, median and mode (mg/dl) of the above data.

**Solution:**

Given, a total of 25 patients admitted to a hospital are tested for levels of blood sugar.

We have to find the __mean__, median and mode of the given data.

Arranging all the observations in __ascending order__.

54 69 75 78 85

65 70 76 80 85

67 71 77 81 85

68 73 77 81 85

68 73 78 83 87

Mean = sum of all observations / total number of observations

Sum of all observations = 54 + 65 + 67 + 68 + 68 + 69 + 70 + 71 + 73 + 73 + 75 + 76 + 77 + 77 + 78 + 78 + 80 + 81 + 81 + 83 + 85 + 85 + 85 + 85 + 87

= 1891

Total number of observations = 25

Mean = 1891/25 = 75.64

Given, n = 25 which is odd

__Median__ = [(n + 1)/2]th observation

= (25 + 1)/2

= 26/2

= 13 th observation

So, median = 77

__Mode__ is defined as the highest frequency of an observation.

Maximum repeated number of the observation = 85

Mode = 85

Therefore, the mean, median and mode of the observations are 75.64, 77 and 85.

**✦ Try This: **A total of 25 patients admitted to a hospital are tested for levels of blood sugar, (mg/dl) and the results obtained were as follows :

86 70 82 66 85

76 60 75 65 86

84 53 70 69 86

72 76 65 83 73

80 74 83 75 78

Find mean, median and mode (mg/dl) of the above data.

**☛ Also Check:** NCERT Solutions for Class 9 Maths Chapter 14

**NCERT Exemplar Class 9 Maths Exercise 14.4 Problem 12**

## A total of 25 patients admitted to a hospital are tested for levels of blood sugar, (mg/dl) and the results obtained were as follows : 87 71 83 67 85 77 69 76 65 85 85 54 70 68 80 73 78 68 85 73 81 78 81 77 75. Find mean, median and mode (mg/dl) of the above data.

**Summary:**

A total of 25 patients admitted to a hospital are tested for levels of blood sugar. The mean, median and mode (mg/dl) of the given data are 75.64, 77 and 85 respectively

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