# Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively (Fig. 9.40). One side of GH is 6 cm long. Find the perimeter of MGHK.

**Solution:**

Given, MGHK is a __parallelogram__

The altitudes MN and MO of parallelogram are 8 cm and 4 cm

The length of one side GH is 6 cm.

We have to find the perimeter of MGHK.

__Area of parallelogram__ = base × corresponding height

= GH × MN

= 6 × 8

= 48 cm²

Now, taking base HK and altitude MO

Area of parallelogram = HK × MO

48 = HK × 4

HK = 48/4

HK = 12 cm

__Perimeter of parallelogram__ = 2(length + breadth)

Perimeter of parallelogram MGHK = 2(GH + HK)

= 2(6 + 12)

= 2(18)

= 36 cm

Therefore, the perimeter of the parallelogram is 36 cm.

**✦ Try This:** The perimeter of a rhombus is 160 cm and one diagonal is 10 cm long then the length of the other diagonal is

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 11

**NCERT Exemplar Class 7 Maths Chapter 9 Problem 86**

## Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively (Fig. 9.40). One side of GH is 6 cm long. Find the perimeter of MGHK.

**Summary:**

Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively (Fig. 9.40). One side of GH is 6 cm long. The perimeter of MGHK is 36 cm

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