# Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm

**Solution:**

Here are the steps of construction:

i) Draw a base BC = 7 cm.

ii) Make angle CBX measuring 75° using a protractor.

iii) With B as center and radius equal to 13cm, draw an arc to intersect ray BX at D.

iv) Join DC.

v) Measure ∠D and make ∠ACD = ∠D. Since sides opposite to equal angles are equal, AC = AD.

vi) Let CY intersect BD at A.

ABC is the required triangle.

Verfication:

We see that,

BC = 7 cm, ∠B = 75° and AB + AC = 13 cm

**☛ Check: **NCERT Solutions Class 9 Maths Chapter 11

**Video Solution:**

## Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm..

Maths NCERT Solutions Class 9 - Chapter 11 Exercise 11.2 Question 1

**Summary:**

It is given that we have to construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm. We have drawn the triangle using a compass and ruler and justified the construction.

**☛ Related Questions:**

- Construct the angles of the following measurements:(i) 30°(ii) 22(1/2)°(iii) 15°
- Construct the following angles and verify by measuring them by a protractor:(i) 75°(ii) 105°(iii) 135°
- Construct an equilateral triangle, given its side and justify the construction.
- Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.

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