# Dice are cubes with dots on each face. Opposite faces of a die always have a total of seven dots on them.

Here are two nets to make dice (cubes); the numbers inserted in each square indicate the number of dots in that box.

Insert suitable numbers in the blanks, remembering that the number on the opposite faces should total to 7.

**Solution:**

As we know dice are cubes with dots on each face. Opposite faces of a die always have a total of seven dots on them. Also, in this question nets to make dice (cubes) is given along with the numbers inserted in each square to indicate the number of dots in that box.

We will be placing the numbers in such a way that the sum of the opposite faces always adds up to 7.

In figure (i) 1^{st} blank net will be number 1 in dice because opposite to it will be 6 as given. 2^{nd} net will be 3 as the opposite face to it will is 4 as given and the last 3^{rd} net will be 2 as the opposite face to it will be 5.

In figure (ii) 1^{st} blank net will be number 5 in dice because opposite to it will be 2 as given. 2^{nd }net will be 6 as the opposite face to it will be 1 as given and the last 3^{rd} net will be 4 as the opposite face to it will be 3.

**Video Solution:**

## Dice are cubes with dots on each face. Opposite faces of a die always have a total of seven dots on them. Here are two nets to make dice (cubes); the numbers inserted in each square indicate the number of dots in that box. Insert suitable numbers in the blanks, remembering that the number on the opposite faces should total to 7.

### Maths NCERT Solutions Class 7 - Chapter 15 Exercise 15.1 Question 2

**Summary:**

Dice are cubes with dots on each face. Opposite faces of a die always have a total of seven dots on them. There are two nets given to make dice (cubes); the numbers inserted in each square indicate the number of dots in that box.

Thus the numbers in the blanks of the first net is 1, 3 and 2 as shown in the diagram above. Thus the numbers in the blanks of the first net is 5, 6 and 4 as shown in the diagram above.