Draw the graphs of the equations x - y + 1 = 0 and 3x + 2y - 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis and shade the triangular region
Solution:
From graph of two linear equations and x-axis, triangle can be shaded, and vertices can be located.
x - y +1 = 0
y = x + 1
x |
0 |
1 |
y = x + 1 |
1 |
2 |
3x + 2 y -12 = 0
2 y = 12 - 3x
y = (12 - 3x)/2
x |
0 |
2 |
y = (12 - 3x)/2 |
6 |
3 |
From graph, Vertices are (-1, 0), (4, 0), and (2, 3)
Video Solution:
Draw the graphs of the equations x - y + 1 = 0 and 3x + 2y - 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis and shade the triangular region.
NCERT Solutions for Class 10 Maths - Chapter 3 Exercise 3.2 Question 7:
Draw the graphs of the equations x - y + 1 = 0 and 3x + 2y - 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the x-axis and shade the triangular region.
For the graphs of the equations -x - y + 1 = 0 and 3x + 2y - 12 = 0, the coordinates of the vertices of the triangle formed by these lines and the x-axis are (-1, 0), (4, 0), and (2, 3).