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# Fill in the blanks to make the following statements true:

(i) (–5) + (– 8) = (– 8) + (............)

(ii) –53 + ............ = –53

(iii) 17 + ............ = 0

(iv) [13 + (– 12)] + (............) = 13 + [(–12) + (–7)]

(v) (– 4) + [15 + (–3)] = [– 4 + 15] + ............

**Solution:**

We have to use different laws of addition.

(i) (-5) + (-8) = (-8) + (-5). [Commutative law of additions]

(ii) -53 + 0 = -53 [Additive Identity] On adding 0 to any integer, it gives the same value.

(iii) 17 + (-17) = 0 [Additive inverse]

(iv) [13 + (-12)] + ( -7) = 13 + [(-12) + (-7)] [Associative law of addition]

(v) (-4) + [15 + (-3)] = [(-4) + 15] + (-3) [Associative law of addition]

**☛ Check: **Class 7 Maths NCERT Solutions Chapter 1

**Video Solution:**

## Fill in the blanks to make the following statements true: (i) (–5) + (– 8) = (– 8) + (............) (ii) –53 + ............ = –53 (iii) 17 + ............ = 0 (iv) [13 + (– 12)] + (............) = 13 + [(–12) + (–7)] (v) (– 4) + [15 + (–3)] = [– 4 + 15] + ............

NCERT Solutions Class 7 Maths Chapter 1 Exercise 1.2 Question 4

**Summary:**

The value of the blanks to make the following statements true: (i) (–5) + (– 8) = (– 8) + (............) (ii) –53 + ............ = –53 (iii) 17 + ............ = 0 (iv) [13 + (– 12)] + (............) = 13 + [(–12) + (–7)] (v) (– 4) + [15 + (–3)] = [– 4 + 15] + ............are (i) -5; (ii) 0; (iii) -17; (iv) -7; (v) -3

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