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# Find the difference of the areas of a sector of angle 120° and its corresponding major sector of a circle of radius 21 cm

**Solution:**

Given, central angle = 120°

Radius of circle = 21 cm

We have to find the difference between the areas of a sector and corresponding major sector of a circle.

Considering circle with radius 21 cm

Area of circle = πr²

= (22/7)(21)²

= 1386 cm²

Considering sector AOBA

Area of a sector = πr²θ/360°

Area of minor sector AOBA = (22/7)(21)²(120°/360°)

= (22)(3)(21)(1/3)

= (22)21

= 462 cm²

Area of major sector = area of circle - area of minor sector

= 1386 - 462

= 924 cm²

Area of major sector and its corresponding major sector ABOA = area of major sector - area of minor sector

= 924 - 462

= 462 cm²

Therefore, the difference between the areas of a sector and corresponding major sector of a circle is 462 cm²

**✦ Try This: **Find the difference of the areas of a sector of angle 90° and its corresponding major sector of a circle of radius 32 cm.

**☛ Also Check: **NCERT Solutions for Class 10 Maths Chapter 12

**NCERT Exemplar Class 10 Maths Exercise 11.4 Problem 20**

## Find the difference of the areas of a sector of angle 120° and its corresponding major sector of a circle of radius 21 cm

**Summary:**

The difference of the areas of a sector of angle 120° and its corresponding major sector of a circle of radius 21 cm is 462 cm²

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