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# In 2007 – 08, the number of students appeared for Class X examination was 1,05,332 and in 2008–09, the number was 1,16,054. If 88,151 students pass the examination in 2007–08 and 103804 students in 2008–09. What is the increase or decrease in pass % in Class X result

**Solution:**

__2007-08__

Students appearing in Class X examination = 1,05,332

Number of students passing = 88,151

Pass % for the year 2007-08 = (88,151/1,05,332) × 100

= 0.8369 × 100

= 83.69%

__2008-09__

Students appearing in Class X examination = 1,16,054

Number of students passing = 1,03,804

Pass % for the year 2007-08 = (1,03,804/1,16,054) × 100

= 0.8944 × 100

= 89.44%

There is an increase in the past percentage from the year 2007-08 to 2008-09 from 83.69% to 89.44% which is an increase of 5.75%

**✦ Try this**: What is the percentage increase in the salary from 5,40,000 to 6,00,000?

**Solution:**

= [(6,00,000 - 5,40,000)/5,40,000] × 100

=[6,00,00/5,40,000]× 100

=100/9 = 11.1111%

**☛ Also Check: **NCERT Solutions for Class 8 Maths Chapter 8

**NCERT Exemplar Class 8 Maths Chapter 9 Problem 72**

## In 2007 – 08, the number of students appeared for Class X examination was 1,05,332 and in 2008–09, the number was 1,16,054. If 88,151 students pass the examination in 2007–08 and 103804 students in 2008–09. What is the increase or decrease in pass % in Class X result

**Summary:**

In 2007 – 08, the number of students appeared for Class X examination was 1,05,332 and in 2008–09, the number was 1,16,054. If 88,151 students pass the examination in 2007–08 and 103804 students in 2008–09. There is an increase in pass % in Class X result by 5.75%

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