from a handpicked tutor in LIVE 1-to-1 classes
In question 2 above (A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base.), if 1 part of red pigment requires 75 ml of base, how much red pigment should we mix with 1800 ml of base?
Let the number of parts of red pigment be x and the parts of base be y.
As the number of parts of red pigment increases, the amount of base also increases in the same ratio. So they are in direct proportion.
Two numbers x and y are said in direct proportion if, the relationship between two quantities is such that if we increase one, the other will also increase, and if we decrease one the other quantity will also decrease.
x/y = k, x = ky
where k is a constant.
Thus, x₁ / y₁ = x₂ / y₂
x₁ = 1, x₂ = ?
y₁ = 75, y₂ = 1800
1 / 75 = x₂ / 1800
x₂ = 1 × 1800 / 75
x₂ = 24
Thus, 24 parts of red pigment should be mixed with 1800 ml of base.
In question (2), above if 1 part of red pigment requires 75 ml of base, how much red pigment should we mix with 1800 ml of base?
NCERT Solutions Class 8 Maths Chapter 13 Exercise 13.1 Question 3
In question (2), above if 1 part of red pigment requires 75 ml of base, 24 parts of red pigment should be mixed with 1800 ml of base.
☛ Related Questions:
- A photograph of a bacteria is enlarged 50,000 times attains a length of 5 cm as shown in the diagram. What is the actual length of the bacteria? If the photograph is enlarged 20,000 times only, what would be its enlarged length?
- In a model of a ship, the mast is 9 cm high, while the mast of the actual ship is 12 cm high. If the length of the actual ship is 28 m, how long is the model ship?
- Suppose 2 kg of sugar contains 9 × 106 crystals. How many sugar crystals are there in (1) 5 kg of sugar? (2) 1.2 kg of sugar?
- Rashmi has a road map with a scale of 1 cm representing 18 km. She drives on a road for 72 km. What would be her distance covered in the map?