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# Observe the following pattern and find the missing digits.

11^{2} = 121

101^{2} = 10201

1001^{2} = 1002001

100001^{2} = 1....2....1

10000001^{2} = ...........

**Solution:**

From the given pattern we see that the square of the given number has the same number of zeros before and after digit 2 as it is present in the original number.

11^{2} = 121

101^{2} = 10201

1001^{2} = 1002001

100001^{2} = 10000200001

10000001^{2} = 100000020000001

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 6

**Video Solution:**

## Observe the following pattern and find the missing digits.

11^{2} = 121

101^{2} = 10201

1001^{2} = 1002001

100001^{2} = 1....2....1

10000001^{2} = ...........

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.1 Question 4

**Summary:**

The missing digits in the numbers for the following pattern

11^{2} = 121

101^{2} = 10201

1001^{2} = 1002001

100001^{2} = 1....2....1

10000001^{2} = ...........

are 10000200001 and 100000020000001

**☛ Related Questions:**

- Observe the following pattern and supply the missing numbers. 112 = 121 1012 = 10201 101012 = 102030201 10101012 = ? ?2 = 10203040504030201
- Using the given pattern, find the missing numbers. 12 + 22 + 22 = 32 22 + 32 + 62 = 72 32 + 42 + 122 = 132 42 + 52 + _2 = 212 52 + -2 + 302 = 312 62 + 72 + _2 = _2
- Without adding, find the sum. (i) 1 + 3 + 5 + 7 + 9 (ii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 +19 (iii) 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
- (i) Express 49 as the sum of 7 odd numbers. (ii) Express 121 as the sum of 11 odd numbers.

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