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# (i) Express 49 as the sum of 7 odd numbers.

(ii) Express 121 as the sum of 11 odd numbers

**Solution:**

We need to express 49 as sum of 7 odd numbers and 121 as sum of 11 odd numbers

We know that the sum of successive odd natural numbers is n^{2}

(i) 49 = (7)^{2}

Therefore, 49 is the sum of first 7 odd natural numbers

49 = 1 + 3 + 5 + 7 + 9 + 11 + 13

(ii) 121 = (11)^{2}

Therefore, 121 is the sum of first 11 odd natural numbers

121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 6

Video Solution:

## (i) Express 49 as the sum of 7 odd numbers (ii) Express 121 as the sum of 11 odd numbers

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.1 Question 8

**Summary:**

The summation of the first 7 odd numbers gives 49 and the summation of the first 11 odd numbers gives 121

**☛ Related Questions:**

- The following numbers are obviously not perfect squares. Give reason. (i) 1057 (ii) 23453 (iii) 7928 (iv) 222222 (v) 64000 (vi) 89722 (vii) 222000 (viii) 505050
- The squares of which of the following would be odd numbers? (i) 431 (ii) 2826 (iii) 7779 (iv) 82004
- Observe the following pattern and find the missing digits. 112 = 121 1012 = 10201 10012 = 1002001 1000012 = 1....2....1 100000012 = ...........
- Observe the following pattern and supply the missing numbers. 112 = 121 1012 = 10201 101012 = 102030201 10101012 = ? ?2 = 10203040504030201

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