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# (i) Express 49 as the sum of 7 odd numbers.

(ii) Express 121 as the sum of 11 odd numbers

**Solution:**

We need to express 49 as sum of 7 odd numbers and 121 as sum of 11 odd numbers

We know that the sum of successive odd natural numbers is n^{2}

(i) 49 = (7)^{2}

Therefore, 49 is the sum of first 7 odd natural numbers

49 = 1 + 3 + 5 + 7 + 9 + 11 + 13

(ii) 121 = (11)^{2}

Therefore, 121 is the sum of first 11 odd natural numbers

121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21

**☛ Check: **NCERT Solutions for Class 8 Maths Chapter 6

Video Solution:

## (i) Express 49 as the sum of 7 odd numbers (ii) Express 121 as the sum of 11 odd numbers

NCERT Solutions for Class 8 Maths Chapter 6 Exercise 6.1 Question 8

**Summary:**

The summation of the first 7 odd numbers gives 49 and the summation of the first 11 odd numbers gives 121

**☛ Related Questions:**

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