# Solve the following equations by trial and error method:

(i) 5p + 2 =17 (ii) 3m - 14 = 4

**Solution:**

According to the given question, we will use the trial and error method to solve the given equations.

(i) 5p + 2 =17.

5p + 2 = L.H.S

By putting, p = 0,

5(0) + 2 = 2 ≠ 17

By putting, p =1,

5(1) + 2 = 7 ≠ 17

By putting, p = 2,

5(2) + 2 = 12 ≠ R.H.S

By putting, p = 3,

5(3) + 2 = 17 = R.H.S

Therefore, p = 3 is a solution of the equation.

ii) 3m – 14 = 4

3m – 14 = L.H.S

By putting, m = 5,

3(5) – 14 = 1 ≠ 6

By putting, m = 6,

3(6) – 14 = 4 = R.H.S.

Therefore, m = 6 is a solution of the equation.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 4

**Video Solution:**

## Solve the following equations by trial and error method: (i) 5p + 2 =17 (ii) 3m - 14 = 4

NCERT Solutions for Class 7 Maths Chapter 4 Exercise 4.1 Question 3

**Summary:**

By using the trial and error method we have solved the following equations: (i) 5p + 2 = 17, p = 3 is a solution of the equation (ii) 3m - 14 = 4, m = 6 is a solution of the equation.

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