# Solve the following equations by trial and error method:

(i) 5p + 2 =17 (ii) 3m - 14 = 4

**Solution:**

Solve the following equations by trial and error method: (i) 5p + 2 = 17 (ii) 3m - 14 = 4. According to the given question, we will use the trial and error method to solve the given equations.(i) 5p + 2 =17.

5p + 2 = L.H.S By putting, p = 0,

5(0) + 2 = 2 ≠ 17

By putting, p =1,

5(1) + 2 = 7 ≠ 17

By putting, p = 2,

5 (2) + 2 = 12 ≠ R.H.S

By putting, p = 3,

5(3) + 2 = 17 = R.H.S

Therefore, p = 3 is a solution of the equation.

ii) 3m – 14 = 4

3m – 14 = L.H.S

By putting, m = 5,

3(5) – 14 = 1 ≠ 6

By putting, m = 6,

3(6) – 14 = 4 = R.H.S.

Therefore, m = 6 is a solution of the equation.

**Video Solution:**

## Solve the following equations by trial and error method: (i) 5p + 2 =17 (ii) 3m - 14 = 4

### NCERT Solutions for Class 7 Maths - Chapter 4 Exercise 4.1 Question 3

Solve the following equations by trial and error method: (i) 5p + 2 = 17 (ii) 3m - 14 = 4

By using the trial and error method: i) p = 3 is a solution of the equation, since L.H.S = R.H.S in this case, ii) m = 6 is a solution of the equation.