# Solve the riddle “What is too much fun for one, enough for two, and means nothing to three?” The answer to this is hidden in the equations given below.

If 4c = 16, then c = ?

If 4e + 8 = 20, then e = ?

If 2r – 3 = 7, then r = ?

If 3t + 8 = 29, then t = ?

If 2s + 4 = 4s, then s = ?

To get the answer substitute the numbers for the letters it equals in the following manner:

**Solution:**

Let’s solve each of the equations

If 4c = 16,

Then c = 16/4

c = 4

If 4e + 8 = 20,

Then 4e = 20 – 8

e = 12/4

e = 3

If 2r – 3 = 7,

Then 2r = 7 + 3

r = 10/2

r = 5

If 3t + 8 = 29,

Then 3t = 29 – 8

t = 21/3

t = 7

If 2s + 4 = 4s,

Then 4s – 2s = 4

2s = 4

s = 4/2

s = 2

Now to get the answer let’s substitute the numbers for the letters it equals in the following manner:

Thus, for the riddle “What is too much fun for one, enough for two, and means nothing to three?” the answer is “secret”.

**✦ Try This: **Find the values and unscramble to answer the riddle. C/I = N/O = 1/2. I have a head and a tail, but no body. The answer is hidden in the clues given below. If 'C' is three lesser than 'N', 'I' is two more than half of 'O', 'O' is the fourth multiple of 4, find C = ? I = ?, N = ? and O = ?.

Answer: COIN, C = 5, O = 8, I = 10 and N = 16

**☛ Also Check: **NCERT Solutions for Class 7 Maths Chapter 4

**NCERT Exemplar Class 7 Maths Chapter 4 Solved Ex 17**

## Solve the riddle “What is too much fun for one, enough for two, and means nothing to three?” The answer to this is hidden in the equations given below. If 4c = 16, then c = ? If 4e + 8 = 20, then e = ? If 2r – 3 = 7, then r = ? If 3t + 8 = 29, then t = ? If 2s + 4 = 4s, then s = ? ---/2, ---/3, ---/4, ---/5, ---/6, ---/7

**Summary:**

Thus, for the riddle “What is too much fun for one, enough for two, and means nothing to three?” the answer is “secret”.

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