# Use the given algebraic expression to complete the table of number patterns

**Solution:**

(i) 2n -1

For n = 100,

⇒ 2 × 100 - 1 = 200 - 1

= 199

(ii) 3n + 2

For n = 5,

⇒ 3 × 5 + 2 = 15 + 2

= 17

For n = 10,

⇒ 3 × 10 + 2 = 30 + 2

= 32

For n = 100,

⇒ 3 × 100 + 2 = 300 + 2

= 302

(iii) 4n +1

For n = 5,

⇒ 4 × 5 + 1 = 20 +1

= 21

For n = 10,

⇒ 4 × 10 + 1 = 40 + 1

= 41

For n = 100,

⇒ 4 × 100 + 1 = 400 + 1

= 401

(iv) 7n + 20

For n = 5,

⇒ 7 × 5 + 20 = 35 + 20

= 55

For n = 10,

⇒ 7 × 10 + 20 = 70 + 20

= 90

For n = 100,

⇒ 7 × 100 + 20 = 700 + 20

= 720

(v) n^{2} + 1

For n = 5,

⇒ 5 × 5 + 1 = 25 + 1

= 26

For n = 10,

10 × 10 + 1 = 100 + 1

= 101

For n = 100,

⇒ 100 × 100 + 1 = 10000 + 1

= 10001

So the complete table is shown below.

**☛ Check: **NCERT Solutions for Class 7 Maths Chapter 12

**Video Solution:**

## Use the given algebraic expression to complete the table of number patterns.

Maths NCERT Solutions Class 7 Chapter 12 Exercise 12.4 Question 2

**Summary:**

Using the given algebraic expression to complete the table of number patterns and putting the value of n = 5, 10 and 100 (i) 2n - 1 is 199 (ii) 3n + 2 is 17, 32 and 302 (iii) 4n + 1 is 21, 41, and 401 (iv) 7n + 20 is 55, 90, and 720 (v) n^{2} +1 is 26, 101, and 10001

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