# Using appropriate properties find:

(i) -2/3 × 3/5 + 5/2 - 3/5 × 1/6

(ii) 2/5 × (-3/7) -1/6 × 3/2 + 1/14 × 2/5

**Solution:**

Rational numbers numbers are in the form of p/q, where p and q can be any integer and q ≠ 0.

By using commutative property of multiplication and addition we proceed with the questions.

(i) -2/3 × 3/5 + 5/2 - 3/5 × 1/6

= 3/5 × (-2/3) + 5/2 - 3/5 × 1/6 [By commutativity of multiplication]

= 3/5 × (-2/3) - 3/5 × 1/6 + 5/2 [By commutativity of addition]

Rearranging to take 3/5 common

= 3/5 × (-2/3 - 1/6) + 5/2

= 3/5 × (-5/6) + 5/2

= -1/2 + 5/2

= 2

(ii) 2/5 × (-3/7) - 1/6 × 3/2 + 1/14 × 2/5

Taking 2/5 as common

= 2/5 × [(-3/7) + 1/14] - 1/6 × 3/2 [By distributive property of multiplication]

= 2/5 × (-3 × 2 + 1)/14 - 1/6 × 3/2

= 2/5 × (-5/14) - 1/6 × 3/2

= -1/7 - 1/4

= -(4 + 7)/28

= -11/28

**Video Solution:**

## Using appropriate properties find: (i) -2/3 × 3/5 + 5/2 - 3/5 × 1/6 (ii) 2/5 × (-3/7) -1/6 × 3/2 + 1/14 × 2/5

### NCERT Solutions Class 8 Maths - Chapter 1 Exercise 1.1 Question 1

**Summary:**

Using appropriate properties, the resultant answer for the expressions are: (i) -2/3 × 3/5 + 5/2 - 3/5 × 1/6 and (ii) 2/5 × (-3/7) -1/6 × 3/2 + 1/14 × 2/5 are 2 and -11/28 respectively.