# Using suitable identity, evaluate the following : 103³

**Solution:**

Given, 103³

We have to evaluate the given __expression__ using a suitable identity.

103³ = (100 + 3)³

Using __algebraic identity__,

(a + b)³ = a³ + b³ + 3ab(a + b)

(100 + 3)³ = (100)³ + (3)³ + 3(100)(3)(100 + 3)

= 1000000 + 27 + 900(103)

= 1000027 + 92700

= 1092727

Therefore, 103³ = 1092727

**✦ Try This: **Using suitable identity, evaluate the following : 102³

Given, 102³

We have to evaluate the given expression using a suitable identity.

102³ = (100 + 2)³

Using algebraic identity,

(a + b)³ = a³ + b³ + 3ab(a + b)

(100 + 2)³ = (100)³ + (2)³ + 3(100)(2)(100 + 2)

= 1000000 + 8 + 600(102)

= 1000008 + 61200

= 1061208

Therefore, 102³ = 1061208

**☛ Also Check: **NCERT Solutions for Class 9 Maths Chapter 2

**NCERT Exemplar Class 9 Maths Exercise 2.3 Problem 25(i)**

## Using suitable identity, evaluate the following : 103³

**Summary:**

The general expressions containing variables of varying degrees, coefficients, positive exponents, and constants are known as polynomial functions. On evaluating, the value of 103³ is 1092727

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