A six-sided die is tossed 3 times. Find the probability of observing three ones in a row is?
Solution:
When a six-sided die is thrown three times the number of outcomes is,
n(S) = 63 = 216
Here n(S) is the sample space.
Let ‘A’ be the event of the die showing three ones, {1, 1, 1}
n(A) = 1
Probability of the die showing three ones P(A) = (Number of favorable outcomes)/(Number of total outcomes)
= n(A)/n(S)
P(A) = 1/216
Therefore, the probability of observing three ones in a row is 1/216.
A six-sided die is tossed 3 times. Find the probability of observing three ones in a row is?
Summary:
When a six-sided die is tossed 3 times, then the probability of observing three ones in a row is 1/216.
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