A six-sided die is tossed 3 times. Find the probability of observing three ones in a row is?

Solution:

When a six-sided die is thrown three times the number of outcomes is,

n(S) = 6³ = 216

Here n(S) is the sample space.

Let ‘A’ be the event of the die showing three ones, {1, 1, 1}

n(A) = 1

Probability of the die showing three ones P(A) = (Number of favorable outcomes)/(Number of total outcomes)

= n(A)/n(S)

P(A) = 1/216

Therefore, the probability of observing three ones in a row is 1/216.

A six-sided die is tossed 3 times. Find the probability of observing three ones in a row is?

Summary:

When a six-sided die is tossed 3 times, then the probability of observing three ones in a row is 1/216.