An inequality is shown below: 
-np - 3 ≥ 7(c - 4) 
Which of the following solves for n?
n ≤ - the quantity 7 times c minus 31 all over p
n ≤ - the quantity 7 times c minus 25 all over p
n ≥ - the quantity 7 times c minus 31 all over p
n ≥ - the quantity 7 times c minus 25 all over p

Solution:

Given: Inequality is -np - 3 ≥ 7(c - 4)

Add ‘3’ on both sides

⇒ -np -3 +3 ≥ 7(c-4) +3

⇒ -np ≥ 7c - 28 +3

⇒ -np ≥ 7c -25

Divide with ‘p’ on both sides

⇒ -n ≥ (7c-25)/p

Multiply both sides with “-1”, we know that in an inequality if -1 is multiplied then the inequality sign is changed

⇒ n ≤ - (7c-25)/p

Hence, n ≤ - the quantity 7 times c minus 25 all over p

An inequality is shown below: 
-np - 3 ≥ 7(c - 4)

Summary:

By solving for n in the inequality -np - 3 ≥ 7(c - 4) , we get n ≤ - the quantity 7 times c minus 25 all over p.