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How do you write an equation in slope-intercept form for a line with points (-3, 1) and (-2, -5)?
Solution:
Given points (-3, 1) and (-2, -5)
We know that slope intercept form is y = mx + c --- [a]
As the line passes through the points (-3, 1) and (-2, -5), they must satisfy the equation
As we have two unknown ‘m’ and ‘c’. We need to find the slope first
slope= m= y2 - y1/x2 - x1
m = -5 - 1 / -2 - (-3)
m = -6/-2 + 3
m = -6/1
Slope = m = -6
Now, substitute x = -3, y = 1 and m = -6 in [a]
1 = (-3)(-6) + c
1= 18 + c
c = 1 - 18
c = -17
Therefore, the equation of line is y = -6x - 17
How do you write an equation in slope-intercept form for a line with points (-3, 1) and (-2, -5)?
Summary:
The equation in slope-intercept form for a line with points (-3, 1) and (-2, -5) is y = -6x - 17.
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