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Solve the system algebraically.
5x + 2y = 10 and 3x + 2y = 6
Solution:
We have been given system of equations:
5x + 2y = 10 --- (1)
3x + 2y = 6 --- (2)
We will use elimination method:
Multiply equation 1 by 3 and equation 2 by 5, we get
⇒ 15x + 6y = 30 --- (3)
⇒ 15x + 10y = 30 --- (4)
Now subtracting equation (4) from equation (3), we get
⇒ -4y = 0
⇒ y = 0
Now, put value of y = 0 in (1) equation,we get
⇒ 5x + 2(0) = 10
⇒ 5x = 10
⇒ x = 2
Therefore, x = 2 and y = 0.
Solve the system algebraically.
5x + 2y = 10 and 3x + 2y = 6
Summary:
By solving the system algebraically, 5x + 2y = 10 and 3x + 2y = 6 we get x = 2 and y = 0.
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