Use summation notation to write the series 49 + 54 + 59 +... for 14 terms

Solution:

The summary notation to represent the series 49 + 54 + 59 +... for 14 terms can be written as :

\(\sum_{n=49}^{n+13}(n+5)\)

The first term is 49 and the thirteenth term from the first term will make the total number of terms 14.

The sequence is basically an arithmetic progression with the first term a = 49 and the difference d = 5.

The 14th term will be:

\(T_{n} = a +(n-1)d\)

\(T_{14} = 49 +(14-1)(5)\)

\(T_{14} = 49 +(13)(5)\)

\(T_{14} = 49 + 65\)

\(T_{14} = 104\)

Use summation notation to write the series 49 + 54 + 59 +... for 14 terms

Summary:

The summation notation to represent the series 49 + 54 + 59 +... for 14 terms can be written as : \(\sum_{n=49}^{n+13}(n+5)\)