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# What is the area of this parallelogram?

40 m^{2}, 72 m^{2}, 92 m^{2}, 112 m^{2}

**Solution:**

In the given parallelogram

There are triangles and a rectangle in between

Area of a triangle = 1/2 × b × h

From the figure, b = 5 m and h = 8 m

Substituting the values

Area of a triangle = 1/2 × 5 × 8 = 20 m^{2}

Area of a rectangle = l × b

From the figure, l = 9 m and b = 8 m

Substituting the values

Area of a rectangle = 9 × 8 = 72 m^{2}

So the area of a rectangle = 2(area of triangle) + area of rectangle

Substituting the values

= 2 (20) + 72

= 40 + 72

= 112 m^{2}

Therefore, the area of the parallelogram is 112 m^{2}.

## What is the area of this parallelogram?

**Summary:**

The area of the parallelogram is 112 m^{2}.

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