What is the slope of the line that contains the points (1,5) and (3,2)?

Solution:

Given two points (1, 5) and (3, 2)

We know that slope intercept form is y = mx + c --- [a]

As the line passes through the points (1, 5) and (3, 2), they must satisfy the equation

As we have two unknown ‘m’ and ‘c’. We need to find the slope first

Slope = m = y₂ - y₁/x₂ - x₁

m = 2 - 5 / 3 - 1

m = -3/2

slope = m = -3/2

Now, substitute x = 1, y = 5 and m = -3/2 in [a]

5 = (-3/2)(1) + c

5 = -3/2 + c

c = 5 + 3/2

c = 6.5

Therefore, the equation of line is y = -3x/2 + 6.5

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What is the slope of the line that contains the points (1, 5) and (3, 2)?

Summary:

The equation in slope-intercept form for a line with points (1, 5) and (3, 2) is y = -3x/2 + 6.5