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# What is the solution of log2x + 68 = 3?

**Solution:**

Given __equation__ :

log2x + 68 = 3

This is a __logarithmic__ function

log2x = 3 - 68 = -65

This is the solution:

log2x = -65

log 2 + logx = -65

0.3010 + log x = -65

log x = -65.301

x = 1/ 10^{65.301}

x = 5 . 10^{-66}

## What is the solution of log2x + 68 = 3?

**Summary:**

The solution of log2x + 68 = 3 is x = 5 . 10^{-66}

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