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What is the solution of log2x + 68 = 3?
Solution:
Given equation :
log2x + 68 = 3
This is a logarithmic function
log2x = 3 - 68 = -65
This is the solution:
log2x = -65
log 2 + logx = -65
0.3010 + log x = -65
log x = -65.301
x = 1/ 1065.301
x = 5 . 10-66
What is the solution of log2x + 68 = 3?
Summary:
The solution of log2x + 68 = 3 is x = 5 . 10-66
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