Which shows the first step in the solution to the equation log₂x + log₂(x - 6) = 4?

Solution:

Given, the equation is log₂x + log₂(x - 6) = 4

We have to find the first step in the solution of the equation.

Using logarithmic laws,

log_ax + log_ay = log_a(xy)

Now, log₂x + log₂(x - 6) = 4 can be written as

log₂ x(x - 6) = 4

Therefore, the first step is log₂x(x - 6) = 4.

Which shows the first step in the solution to the equation log₂x + log₂(x - 6) = 4?

Summary:

The first step in the solution to the equation log₂x + log₂(x - 6) = 4 is log₂ x(x - 6) = 4.