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# Which value must be added to the expression x^{2}-3x to make it a perfect-square trinomial?

**Solution:**

Given: Expression is x^{2} - 3x

Standard form of a perfect square trinomial is

(x - a)^{2} = x^{2} - 2ax + a^{2}

Add c as the value that must be added in the given equation

x^{2} - 3x + c

Now let us equate it to the standard form

3x = 2ax, c = a^{2}

So we get,

3x = 2ax

a = 3/2

c = (3/2)^{2} = 9/4

Here,

(x - 3/2)^{2} = x^{2} - 3x + 9/4

Therefore, the value that must be added is 9/4.

## Which value must be added to the expression x^{2 }- 3x to make it a perfect-square trinomial?

**Summary:**

The value that must be added to the expression x^{2 }- 3x to make it a perfect-square trinomial is 9/4.

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