Write the equation of the circle with center (3, 2) and (-6, -4) a point on the circle.

Solution:

The standard form of the equation of a circle is given by

(x - a)2 + (y - b)2 = r2

Where, a and b are the coordinates of the centre

r is the radius

Given, centre = (3, 2) and (x,y) = (-6 , -4)

Substituting the values in standard form of equation we get,

(-6 - 3)2 + (-4 - 2)2 = r2

(-9)2 + (-6)2 = r2

r2 = 81 + 36

r = √117

Thus, the radius of the circle is √117 units.

The equation of a circle can be written as 

(x - 3)2 + (y - 2)2 = (√117)2

(x - 3)2 + (y - 2)2 = 117

Therefore, the equation of a circle is (x - 3)2 + (y - 2)2 = 117.

Write the equation of the circle with center (3, 2) and (-6, -4) a point on the circle.

Summary:

The equation of the circle with center (3, 2) and (-6, -4) a point on the circle is (x - 3)2 + (y - 2)2 = 117.

Math worksheets and
visual curriculum