# A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?

**Solution:**

Since the cylindrical bowl is filled with soup, the volume of the soup will be equal to the volume of the cylindrical bowl.

The volume of a cylinder of base radius r, and height h = πr^{2}h

The amount of soup to be prepared will be the product of the volume of soup in each bowl and the total number of patients.

Diameter of the bowl = 7 cm

Radius of the bowl, r = 7/2 cm = 3.5cm

Height of the bowl, h = 4 cm

The volume of soup in each bowl = πr^{2}h

= 22/7 × 3.5 cm × 3.5 cm × 4 cm

= 154 cm^{3}

The volume of soup for 1 patient = 154 cm^{3}

Thus, the volume of soup for 250 patients

= 250 × 154 cm^{3}

= 38500 cm^{3}

= 38500 / 1000 (Since, 1000 cm^{3} = 1l)

= 38.5 l

The hospital has to prepare 38.5 litres of soup daily to serve 250 patients.

**☛ Check: **NCERT Solutions for Class 9 Maths Chapter 13

**Video Solution:**

## A patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, how much soup the hospital has to prepare daily to serve 250 patients?

NCERT Solutions for Class 9 Maths Chapter 13 Exercise 13.6 Question 8

**Summary:**

It is given that the patient in a hospital is given soup daily in a cylindrical bowl of diameter 7 cm. If the bowl is filled with soup to a height of 4 cm, we have found that the hospital has to prepare 38.5 litres of soup daily to serve 250 patients.

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